Diketahui balok ABCDEFGH dengan panjang AB=8cm BC=6cm AE=5cm maka panjang diagonal ruangnya adalah

AE = CG

Menghitung diagonal sisi AC
[tex]{ac}^{2} = {ab}^{2} + {bc}^{2} \\{ac}^{2} = {8}^{2} + {6}^{2} \\ {ac}^{2} = 64 + 36 \\ {ac}^{2} = 100 \\ {ac} = \sqrt{100} = 10 \: cm[/tex]

Menghitung diagonal ruang AG
[tex]{ag}^{2} = {ac}^{2} + {cg}^{2} \\{ag}^{2} = {10}^{2} + {5}^{2} \\ {ag}^{2} = 100 + 25 \\ {ag}^{2} = 125 \\ {ag} = \sqrt{125} = 5 \sqrt{5} \: cm[/tex]