Matematika

Pertanyaan

jika P(X) = X(X^3+3x^2+2) ,nilai P(-1)

2 Jawaban


  • [tex]p( - 1) = ( - 1)( { - 1}^{3}+ 3( { - 1}^{2}) + 2)[/tex]
    [tex]p( - 1) = ( - 1)( - 1 + 3 + 2)[/tex]
    [tex]p( - 1) = ( - 1)(4)[/tex]
    [tex]p( - 1) = - 4[/tex]

  • p(x) = x(x^3 + 3x^2 +2)
    p(-1) = ?

    (Masukkan -1 ke dalam fungsi)
    p(-1) = -1((-1)^3 + 3(-1)^2 + 2
    p(-1) = -1(1 + 3 + 2)
    p(-1) = -1 . 6

    p(-1) = -6

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