Diketahui nilai cos α 4/9,tentukan nilai cotan α

sa=4
mi=9
de=√(9^2 - 4^2)
=√65

cot a = 4/√65 = (4√65)/65

◾ Materi : Trigonometri
◾ Sub materi : Trigonometri
◾ Mapel : Matematika
◾ Keyword :

Jawab :
cos α = 4/9
x/r = 4/9

x = 4 dan r = 9

cari y
y² = r² - x²
y² = 9² - 4²
y² = 81-16
y² = 65
y = √65

cotan α = 1/tan α
cotan α = 1/y/x
cotan α = x/y
cotan α = 4/√65
cotan α = 4√65 / 65

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-vin