Berapa nilai X dari 6X2-6X-1=0 ?

[tex]6 \times 2 - 6x - 1 = 0 \\ 12 - 6x - 1 = 0 \\ - 6x = - 12 + 1 \\ - 6x = - 11 \\ x = \frac{ - 11}{ - 6} \\ x = \frac{11}{6} atau \: 1 \frac{5}{6} [/tex]
semoga membantu

[tex]6 {x}^{2} - 6x - 1 = 0 \\ {x}^{2} - x - \frac{1}{6} = 0 \\ {(x - \frac{1}{2} )}^{2} - \frac{1}{4} - \frac{1}{6} = 0 \\ {(x - \frac{1}{2}) }^{2} = \frac{5}{12} \\ x - \frac{1}{2} = \: + - \frac{ \sqrt{5} }{2 \sqrt{3} } \\ x1 = \frac{ \sqrt{5} }{2 \sqrt{3} } + \frac{1}{2} = \frac{ \sqrt{15} + 3 }{6} \\ x2 = \frac{3 - \sqrt{15} }{6} [/tex]