Dikketahui rumus suatu fungi adalah f(x) =px+q . Jika nilai f(2)=5 dan f(5)=14 ,maka f(x-2)=

2p+q=5
5p+q=14
______ _
-3p=-9
p=3

2(3)+q=5
q=-1

f(x)=3x-1
f(x-2)=3(x-2)-1=3x-6-1=3x-7

F(x) =px +q
F(2) = 2p + q = 5
F(5) = 5p + q = 14
_______________-
-3p = -9
p. = 3

5p + q = 14
15 + q =14
q = -1
F(x) = 3x - 1
F(-2) = 3(-2)-1
= -6 -1= -7