tolong bantu jawab soal matematika

[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \frac{y - 0}{6 - 0} = \frac{x + 9}{0 + 9} \\ \frac{y}{6} = \frac{x + 9}{9} \\ 9y = 6x + 54 \\ y = \frac{2}{3} x + 6[/tex]
maka di dapat gradien (m) = 2/3
karena tegak lurus, maka m1 × m2 = -1, sehingga m2 = -1 : (2/3) = -1 × 3/2 = -3/2

persamaan garis h :
[tex]y - y1 = m(x - x1) \\ y - 0 = ( - \frac{3}{2} )(x - 0) \\ y = - \frac{3}{2} x \\ 2y = - 3x \\ 3x + 2y = 0[/tex]