750 gram air suhunya 0°C dicampur dengan 500 gram air suhunya 100°C , jika kalor jenis air 1 kal/gram °C ,, tentukan suhu akhir campuran?

m1 = 0.75 kg
m2 = 0.5 kg
T1 = 0°C
T2 = 100°C

Ql = Qt
M1 x C x ∆T = M2 x C x ∆T
M1 x ∆T = M2 x ∆T
0.75 x (T-0) = 0.5 x (100-T)
0.75T = 50 - 0.5T
1.25 T = 50
T = (50)/(1.25)
T = 40°C

semoga membantu (y)