tentukan persamaan garis yang melalui titik: m(1,1)&n(-6,4)

(y - 1) / (4-1) = (x - 1)/(-6-1)
(y -1) / 3 = (x -1) / -7
-7y + 7 = 3x -3
-7y = 3x -10
3x +7y -10 =0

(1,1)
 x1=1
 y1=1
(-6,4)
 x2= -6
 y2=  4

[tex] \frac{y-y1}{y2-y1} = \frac{x-x1}{x2-x1} [/tex]
= [tex] \frac{y-1}{4-1} = \frac{x-1}{-6-1} [/tex]
= [tex] \frac{y-1}{3} = \frac{x-1}{-7} [/tex]
= 3(x-1)=  -7(y-1)
= 3x -3 = -7y + 7
= 3x -3 +7y - 7= 0
= 3x + 7y - 10 = 0 atau 3x + 7y = 10 atau 7y = -3x + 10