tolong ya...........

5. perbandingan..
misalkan :
6 cm = sisi AD
4 cm = sisi DB
3 cm = sisi DE
x cm = sisi BC (sesuai gambar)
maka :
[tex] \: \: \: \: \: \frac{ad}{ab} = \frac{de}{bc} \\ \frac{6}{6 + 4} = \frac{3}{x} \\ \: \: \: \: \: \frac{6}{10} = \frac{3}{x} \\ \: \: \: \: \: \: 6x = 3 \times 10 \\ \: \: \: \: \: \: 6x = 30 \\ \: \: \: \: \: \: \: \: x = \frac{30}{6} \\ \: \: \: \: \: \: \: \: x = 5[/tex]

nomor 6.
[tex] \: \: \: \: \: \frac{ad}{ab} = \frac{de}{bc} \\ \frac{6}{6 + 4} = \frac{y}{10} \\ \: \: \: \: \: \frac{6}{10} = \frac{y}{10} \\ \: \: \: \: 10y = 60 \\ \: \: \: \: \: \: \: \: y = \frac{60}{10} \\ \: \: \: \: \: \: \: \: y = 6[/tex]

[tex] \: \: \: \: \: \frac{ad}{ab} = \frac{ae}{ac} \\ \frac{6}{6 + 4} = \frac{x}{x + 2} \\ \\ \: \: \: \: \: \frac{6}{10} = \frac{x}{x + 2} \\ \: \: \: 10x = 6(x + 2) \\ \: \: \: 10x = 6x + 12 \\ 10x - 6x = 12 \\ 4x = 12 \\ x = \frac{12}{4} \\ x = 3[/tex]