Diketahui A=(xIx>5, x bilangan asli), B=(xI3
Matematika
liniafianti
Pertanyaan
Diketahui A=(xIx>5, x bilangan asli), B=(xI3<x<8, x bilangan asli), dan C=(xI5<x<10, x bilangan asli). Dengan cara mendaftar anggotanya, tentukan:
a. (AnB)u(BnC)
b. (AuC)n(AuB)
c. (BuC)n(AuC)
a. (AnB)u(BnC)
b. (AuC)n(AuB)
c. (BuC)n(AuC)
2 Jawaban
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1. Jawaban akwilaelmadhitya
A=6,7,8,9,10,......
B=4,5,6,7
C=6,7,8,9
a. (AnB)u(BnC)
=(6,7)u(6,7)
=6,7
b. (AuC)n(AuB)
=(6,7,8,9,10,....)n(4,5,6,7,8,9,10,....)
=6,7,8,9,10,....
c, (BuC)n(AuC)
=(4,5,6,7,8,9)n(6,7,8,9,10,....)
=6,7,8,9 -
2. Jawaban nyakfirzah
A={6,7,8,9,10....},c={11,12,13,14},b={9,10,11,12}
a.{11,12,13,14} gabung {11,12}={11,12,13,14}
b.{6,7,8,9,10,11,12,13,14...} IRIS {6,7,8,9,10,11,12...}={6,7,8,9,10,11,12,13,14...}
c.{9,10,11,12,13,14} iris {6,7,8,9,10,11,12,13,14...}={9,10,11,12,13,14...}