sebanyak 2kg air di panaskan hingga mendidih.

Qa-b= m×c×*delta t
= 2×2100×(0-(-5))
= 4200×5
= 21000 Joule
Qb-c= m×les
= 2×334000
= 668000
Jadi, Qa-c= Qa-b+Qb-c
=668000+21000
= 689000/1000= 689 kJ