4¹/5-2⅓×1½ adalahh.....

≡ penyelesaian :

[tex] = 4 \frac{1}{5} - (2 \frac{1}{3} \times 1 \frac{1}{2} ) \\ \\ = \frac{21}{5} - ( \frac{7}{3} \times \frac{3}{2} ) \\ \\ = \frac{21}{5} - \frac{21}{6} \\ \\ = \frac{126 - 105}{30} \\ \\ = \frac{21}{30} = \frac{7}{10} [/tex]