hitung pH larutan NaH2PO4 0,01 M (Ka=6,2.10^-8

Larutannya termasuk larutan garam hidrolisis bersifat basa.
[H+] = √(Kw/Kb) [garam]
= √(10^-14/6,2x10^-8) (0,01) = 4,0 x 10^-5
pH = - log 4,0x10^-5 = 5 - log 4
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