Matematika

Pertanyaan

1. Nilai x yang memenuhi persamaan 3 ( x + 6 ) + 2(1-2x) = 10(x+4) + 2 adalah ......
(A.)-2 (B.) 7 (C) 11 (D) 16

2. Jika 5(x-2)-5 = 2(x + 3) + 3, nilai x-5 adalah...
(A.) 0 (B) 3 (C) 5 (D) 8

3. Nilai x yang memenuhi persamaan
3(3x + 2/3) = 5(2x - 1/4) adalah...
(A) -13/4 (B) -7/4 (C) 7/4 (D) 13/4


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1 Jawaban

  • 1. 3 ( x + 6 ) + 2(1-2x) = 10(x+4) + 2
    =3x + 18+2-4x = 10x+40+2
    = 3x -4x +20 = 10x + 42
    = - x + 20 = 10x + 42
    = - x - 10x = 42 - 20
    = -11x = 22
    x = 22 /-11
    x = - 2 * A*

    2. 5(x-2)-5 = 2(x + 3) + 3, nilai x-5
    5x - 10-5 = 2x + 6+3
    5x - 15 = 2x + 9
    5x - 2x = 15+ 9
    3x = 24
    x = 24 / 3
    x = 8

    jadi x -5 = 8 - 5 = 3 * B*

    3. 3(3x + 2/3) = 5(2x - 1/4)
    9x + 2 = 10x -5/4
    2 + 5/4 = 10x-9x
    8/4 + 5/4 = x
    x = 13/4. *D*

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