Tentukan nilai pH 500 mL larutan NaOH 0,02 M! Beserta caranya

Mapel: Kimia
Kelas: XI
Materi: Asam Basa

Jawab
Mencari Mol

NaOH → Na+ + OH-

[OH-] = M×Vb
[OH-] = 0,02×1
[OH-] = 2×10-²

pOH= -log[OH-]
pOH= -log2×10-²
pOH= 2-log2

pH= pKw - pOH
pH= 14-(2-log2)
pH = 12+log2

log2= 0,3