Diketahui ³log4=p dan ³log 5=q nilai dari 6log 240

³log4 = p
³log2 = p/2
³log5 = q

6log240 = ³log240/³log6
= ³log(4² x 3 x 5)/³log(2 x 3)
= (2³log4 + ³log3 + ³log5)/(³log2 + ³log3)
= (2p + 1 + q)/(p/2 + 1)
= (2p + 1 + q) ÷ (p+1)/2
= (2p + 1 + q) x 2/(p+1)
= 2(2p + 1 + q)/(p+1)