3log4=p,dan 3log5=q.nilai dari 6log240=

[tex]3log4 = p \\ \frac{log4}{log3} = p \\ log4 = plog3 \\ \\ 3log5 = q \\ \frac{log5}{log3} = q \\ log5 = qlog3 \\ \\ = 6log240 \\ = \frac{log240}{log6} \\ = \frac{log(3 \times {4}^{2} \times 5)}{log(2 \times 3)} \\ = \frac{log3 + 2log4 + log5}{log2 + log3} \\ = \frac{log3 + 2log4 + log5}{ \frac{1}{2} log4 + log3} \\ = \frac{log3 + 2plog3 + qlog3}{ \frac{p}{2}log3 + log3 } \\ = \frac{1 + 2p + q}{ \frac{p}{2} + 1 } \\ = \frac{2 + 4p + 2q}{p + 2} [/tex]