nilai optimum dari fungsi y= -x²+x-6

Kelas 10 Matematika
Bab Fungsi Kuadrat

y = -x² + x - 6
a = -1; b = 1; c = -6

Sumbu simetri
= -b/2a
= -1/(2 . -1)
= 1/2

Nilai optimum
= - (1/2)² + 1/2 - 6
= -1/4 + 2/4 - 24/4
= -23/4
= -5 3/4