Kimia

Pertanyaan

Harga pH larutan H2SO4 0,01 M sebesar....

1 Jawaban

  • Mapel: Kimia
    Kelas: XI
    Materi: Asam Basa

    Jawab

    H2SO4→ 2H+ + SO4²-

    [H+] = a × Ma
    [H+] = 2 × 0.01
    [H+] = 0.02M
    [H+] = 2×10-²

    pH= -log[H+]
    pH= -log2×10-²
    pH= 2-log2
    pH= 2-0.3
    pH= 1.7

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